How To Skip The First X Nodes During foreach Loop In XSLT



TODO:

Have you ever wanted to skip the first X nodes during a foreach loop?  In my case, I was taking a flat CSV file and turning it into a generic XML document.  I was then using XSLT to transform that document into a meaningful XML document representing Customer.  The first 2 rows of my CSV file, were header and file information only, therfore I did not want to process them.  Rather than hard code the rows to skip in a pre-processor for the flat file, I can just transform the data to my final document, and then skip X rows in XSLT.  I was using XSLT anyhow to create my customer document, so it was just as easy to put the logic there.

 

SOLUTION:

 

<?xml version='1.0' ?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
  <xsl:template match="/">
    <Customers>
      <xsl:variable name="myRootNode" select="."/>
      <xsl:for-each select="$myRootNode/MyNodes/Node">
        <xsl:variable name="myNode" select="."/>
        <xsl:if test="position() > 2">
           <Customer>
             Do Your Other XSLT Stuff Here ...
           </Customer>
        </xsl:if>
      </xsl:for-each>
    </Customers>
  </xsl:template>
</xsl:stylesheet>

 

NOTES:

This will skip the first 2 nodes I encounter, which represents the first 2 header rows that I had in my document.